Integral of 7x+6 dx

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$$\int\limits_{0}^{1} \left(7 x + 6\right)\, dx$$

Integral(7*x + 6, (x, 0, 1))

Detail solution

Integrate term-by-term:
1. The integral of a constant times a function is the constant times the integral of the function:
  
  $\int 7 x\, dx = 7 \int x\, dx$
  1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :
    
    $\int x\, dx = \frac{x^{2}}{2}$
  So, the result is: $\frac{7 x^{2}}{2}$
1. The integral of a constant is the constant times the variable of integration:
  
  $\int 6\, dx = 6 x$
The result is: $\frac{7 x^{2}}{2} + 6 x$
Now simplify:

$\frac{x \left(7 x + 12\right)}{2}$
Add the constant of integration:

$\frac{x \left(7 x + 12\right)}{2}+ \mathrm{constant}$

The answer is:

$\frac{x \left(7 x + 12\right)}{2}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                            2
 |                          7*x 
 | (7*x + 6) dx = C + 6*x + ----
 |                           2  
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$$\int \left(7 x + 6\right)\, dx = C + \frac{7 x^{2}}{2} + 6 x$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

19/2

$$\frac{19}{2}$$

19/2

$$\frac{19}{2}$$

19/2

Numerical answer [src]

9.5

9.5

Use the examples entering the upper and lower limits of integration.