Integral of (4x^3-3x^2+5) dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫4x3dx=4∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: x4
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The integral of a constant times a function is the constant times the integral of the function:
∫(−3x2)dx=−3∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: −x3
The result is: x4−x3
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The integral of a constant is the constant times the variable of integration:
∫5dx=5x
The result is: x4−x3+5x
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Now simplify:
x(x3−x2+5)
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Add the constant of integration:
x(x3−x2+5)+constant
The answer is:
x(x3−x2+5)+constant
The answer (Indefinite)
[src]
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| / 3 2 \ 4 3
| \4*x - 3*x + 5/ dx = C + x - x + 5*x
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/
∫((4x3−3x2)+5)dx=C+x4−x3+5x
−l4+l3−5l+69
=
−l4+l3−5l+69
Use the examples entering the upper and lower limits of integration.