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Integral of d{x}:
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Graphing y =:
3x^2+x-4
Identical expressions
3x^ two +x- four
3x squared plus x minus 4
3x to the power of two plus x minus four
3x2+x-4
3x²+x-4
3x to the power of 2+x-4
3x^2+x-4dx
Similar expressions
3x^2-x-4
3x^2+x+4

Solving integrals/ 3x^2+x-4

Integral of 3x^2+x-4 dx

The solution

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  1                  
  /                  
 |                   
 |  /   2        \   
 |  \3*x  + x - 4/ dx
 |                   
/                    
2

$$\int\limits_{2}^{1} \left(3 x^{2} + x - 4\right)\, dx$$

Integral(3*x^2 + x - 1*4, (x, 2, 1))

Detail solution

Integrate term-by-term:
1. The integral of a constant times a function is the constant times the integral of the function:
  
  $\int 3 x^{2}\, dx = 3 \int x^{2}\, dx$
  1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :
    
    $\int x^{2}\, dx = \frac{x^{3}}{3}$
  So, the result is: $x^{3}$
1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :
  
  $\int x\, dx = \frac{x^{2}}{2}$
1. The integral of a constant is the constant times the variable of integration:
  
  $\int \left(\left(-1\right) 4\right)\, dx = - 4 x$
The result is: $x^{3} + \frac{x^{2}}{2} - 4 x$
Now simplify:

$\frac{x \left(2 x^{2} + x - 8\right)}{2}$
Add the constant of integration:

$\frac{x \left(2 x^{2} + x - 8\right)}{2}+ \mathrm{constant}$

The answer is:

$\frac{x \left(2 x^{2} + x - 8\right)}{2}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                     
 |                               2      
 | /   2        \           3   x       
 | \3*x  + x - 4/ dx = C + x  + -- - 4*x
 |                              2       
/

$$\int \left(3 x^{2} + x - 4\right)\, dx = C + x^{3} + \frac{x^{2}}{2} - 4 x$$

Simplify

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Plot the graph f(x)

The answer [src]

-9/2

$$- \frac{9}{2}$$

-9/2

$$- \frac{9}{2}$$

Упростить

Numerical answer [src]

-4.5

-4.5

The graph

Use the examples entering the upper and lower limits of integration.

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Identical expressions

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Integral of 3x^2+x-4 dx

Limits of integration:

The graph:

Piecewise:

The solution