Integral of 3x^2+2x+1 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫3x2dx=3∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: x3
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The integral of a constant times a function is the constant times the integral of the function:
∫2xdx=2∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: x2
The result is: x3+x2
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: x3+x2+x
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Now simplify:
x(x2+x+1)
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Add the constant of integration:
x(x2+x+1)+constant
The answer is:
x(x2+x+1)+constant
The answer (Indefinite)
[src]
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| / 2 \ 2 3
| \3*x + 2*x + 1/ dx = C + x + x + x
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∫((3x2+2x)+1)dx=C+x3+x2+x
The graph
Use the examples entering the upper and lower limits of integration.