Integral of (3x^2-4x-(2/x)) dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫3x2dx=3∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: x3
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The integral of a constant times a function is the constant times the integral of the function:
∫(−4x)dx=−4∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −2x2
The result is: x3−2x2
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x2)dx=−2∫x1dx
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The integral of x1 is log(x).
So, the result is: −2log(x)
The result is: x3−2x2−2log(x)
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Add the constant of integration:
x3−2x2−2log(x)+constant
The answer is:
x3−2x2−2log(x)+constant
The answer (Indefinite)
[src]
/
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| / 2 2\ 3 2
| |3*x - 4*x - -| dx = C + x - 2*x - 2*log(x)
| \ x/
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/
∫((3x2−4x)−x2)dx=C+x3−2x2−2log(x)
The graph
−1+2log(2)
=
−1+2log(2)
Use the examples entering the upper and lower limits of integration.