Integral of e^(8x) dx
The solution
Detail solution
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Let u=8x.
Then let du=8dx and substitute 8du:
∫8eudu
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: 8eu
Now substitute u back in:
8e8x
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Add the constant of integration:
8e8x+constant
The answer is:
8e8x+constant
The answer (Indefinite)
[src]
/
| 8*x
| 8*x e
| E dx = C + ----
| 8
/
∫e8xdx=C+8e8x
The graph
−81+8e8
=
−81+8e8
Use the examples entering the upper and lower limits of integration.