Integral of (2x-5)^7 dx

1. There are multiple ways to do this integral.

   Method #1

   1. Let $u = 2 x - 5$.

      Then let $du = 2 dx$ and substitute $\frac{du}{2}$:

      $$\int \frac{u^{7}}{4}\, du$$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int \frac{u^{7}}{2}\, du = \frac{\int u^{7}\, du}{2}$$

         1. The integral of $u^{n}$ is $\frac{u^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int u^{7}\, du = \frac{u^{8}}{8}$$

         So, the result is: $\frac{u^{8}}{16}$

      Now substitute $u$ back in:

      $$\frac{\left(2 x - 5\right)^{8}}{16}$$

   Method #2

   1. Rewrite the integrand:

      $$\left(2 x - 5\right)^{7} = 128 x^{7} - 2240 x^{6} + 16800 x^{5} - 70000 x^{4} + 175000 x^{3} - 262500 x^{2} + 218750 x - 78125$$

   2. Integrate term-by-term:

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 128 x^{7}\, dx = 128 \int x^{7}\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x^{7}\, dx = \frac{x^{8}}{8}$$

         So, the result is: $16 x^{8}$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int \left(- 2240 x^{6}\right)\, dx = - 2240 \int x^{6}\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x^{6}\, dx = \frac{x^{7}}{7}$$

         So, the result is: $- 320 x^{7}$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 16800 x^{5}\, dx = 16800 \int x^{5}\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x^{5}\, dx = \frac{x^{6}}{6}$$

         So, the result is: $2800 x^{6}$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int \left(- 70000 x^{4}\right)\, dx = - 70000 \int x^{4}\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x^{4}\, dx = \frac{x^{5}}{5}$$

         So, the result is: $- 14000 x^{5}$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 175000 x^{3}\, dx = 175000 \int x^{3}\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x^{3}\, dx = \frac{x^{4}}{4}$$

         So, the result is: $43750 x^{4}$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int \left(- 262500 x^{2}\right)\, dx = - 262500 \int x^{2}\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x^{2}\, dx = \frac{x^{3}}{3}$$

         So, the result is: $- 87500 x^{3}$

      1. The integral of a constant times a function is the constant times the integral of the function:

         $$\int 218750 x\, dx = 218750 \int x\, dx$$

         1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$:

            $$\int x\, dx = \frac{x^{2}}{2}$$

         So, the result is: $109375 x^{2}$

      1. The integral of a constant is the constant times the variable of integration:

         $$\int \left(-78125\right)\, dx = - 78125 x$$

      The result is: $16 x^{8} - 320 x^{7} + 2800 x^{6} - 14000 x^{5} + 43750 x^{4} - 87500 x^{3} + 109375 x^{2} - 78125 x$

2. Now simplify:

   $$\frac{\left(2 x - 5\right)^{8}}{16}$$

3. Add the constant of integration:

   $$\frac{\left(2 x - 5\right)^{8}}{16}+ \mathrm{constant}$$

The answer is:

$$\frac{\left(2 x - 5\right)^{8}}{16}+ \mathrm{constant}$$