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x^2*log(16)x>=log(16)x^5+x*log(2)x

  • How to use it?

  • Inequation:
  • ctg^2x+ctgx>=0
  • x^2*log(16)x>=log(16)x^5+x*log(2)x x^2*log(16)x>=log(16)x^5+x*log(2)x
  • log31(31x+2)<=0
  • tan(x)≥1 tan(x)≥1

  • Identical expressions

  • x^ two *log(sixteen)x>=log(sixteen)x^ five +x*log(two)x
  • x squared multiply by logarithm of (16)x greater than or equal to logarithm of (16)x to the power of 5 plus x multiply by logarithm of (2)x
  • x to the power of two multiply by logarithm of (sixteen)x greater than or equal to logarithm of (sixteen)x to the power of five plus x multiply by logarithm of (two)x
  • x2*log(16)x>=log(16)x5+x*log(2)x
  • x2*log16x>=log16x5+x*log2x
  • x²*log(16)x>=log(16)x⁵+x*log(2)x
  • x to the power of 2*log(16)x>=log(16)x to the power of 5+x*log(2)x
  • x^2log(16)x>=log(16)x^5+xlog(2)x
  • x2log(16)x>=log(16)x5+xlog(2)x
  • x2log16x>=log16x5+xlog2x
  • x^2log16x>=log16x^5+xlog2x

  • Similar expressions

  • x^2*log(16)x>=log(16)x^5-x*log(2)x
Solving inequalities/ x^2*log(16)x>=log(16)x^5+x*log(2)x

x^2*log(16)x>=log(16)x^5+x*log(2)x inequation

A inequation with variable

The solution

You have entered [src] 
 2                       5             
x *log(16)*x >= log(16)*x  + x*log(2)*x
$$x x^{2} \log{\left(16 \right)} \geq x^{5} \log{\left(16 \right)} + x x \log{\left(2 \right)}$$ 
x*x^2*log(16) >= x^5*log(16) + x*x*log(2)
Solving inequality on a graph
The graph
x^2*log(16)x>=log(16)x^5+x*log(2)x inequation
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