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How to use it?
- Inequation:
- x^log625(2+x)>=log5(x^2+4x+4)
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((2-x^2)*(x-3)^3)/((x+1)*(x^2-3x-4))>=0
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(31-5*2^x)*1/(4^x-24*2^x+128)>=0,25
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6x^2+17<0
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Identical expressions
- x^log6 two 5(two +x)>=log5(x^2+ four x+4)
- x to the power of logarithm of 625(2 plus x) greater than or equal to logarithm of 5(x squared plus 4x plus 4)
- x to the power of logarithm of 6 two 5(two plus x) greater than or equal to logarithm of 5(x squared plus four x plus 4)
- xlog625(2+x)>=log5(x2+4x+4)
- xlog6252+x>=log5x2+4x+4
- x^log625(2+x)>=log5(x²+4x+4)
- x to the power of log625(2+x)>=log5(x to the power of 2+4x+4)
- x^log6252+x>=log5x^2+4x+4
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Similar expressions
- x^log625(2-x)>=log5(x^2+4x+4)
- x^log625(2+x)>=log5(x^2-4x+4)
- x^log625(2+x)>=log5(x^2+4x-4)
x^log625(2+x)>=log5(x^2+4x+4) inequation
The solution
You have entered
[src]
log(2 + x)
---------- / 2 \
log(625) log\x + 4*x + 4/
x >= -----------------
log(5)
$$x^{\frac{\log{\left(x + 2 \right)}}{\log{\left(625 \right)}}} \geq \frac{\log{\left(x^{2} + 4 x + 4 \right)}}{\log{\left(5 \right)}}$$
x^(log(x + 2)/log(625)) >= log(x^2 + 4*x + 4)/log(5)