Mister Exam
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-
How to use it?
- Inequation:
- 2x/3-(x+)1/4<=-2
- 4/(x-3)-x<0
- (x-2):(x+5)>0
- 3*x+4<2*x+5
- Graphing y =:
-
asin(x)
- Equation:
-
asin(x)
- Limit of the function:
-
asin(x)
-
Identical expressions
- asin(x)<=п/ two
- arc sinus of e of (x) less than or equal to п divide by 2
- arc sinus of e of (x) less than or equal to п divide by two
- asinx<=п/2
- asin(x)<=п divide by 2
-
Similar expressions
- asin(x-1)>pi/6
- a^2+2a-cos^2x-2asinx>2
- arcsin(x)<=п/2
- arcsinx<=п/2
asin(x)<=п/2 inequation
The solution
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pi
asin(x) <= --
2
$$\operatorname{asin}{\left(x \right)} \leq \frac{\pi}{2}$$
asin(x) <= pi/2
Detail solution
Given the inequality:
$$\operatorname{asin}{\left(x \right)} \leq \frac{\pi}{2}$$
To solve this inequality, we must first solve the corresponding equation:
$$\operatorname{asin}{\left(x \right)} = \frac{\pi}{2}$$
Solve:
$$x_{1} = 1$$
$$x_{1} = 1$$
This roots
$$x_{1} = 1$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} \leq x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 1$$
=
$$\frac{9}{10}$$
substitute to the expression
$$\operatorname{asin}{\left(x \right)} \leq \frac{\pi}{2}$$
$$\operatorname{asin}{\left(\frac{9}{10} \right)} \leq \frac{\pi}{2}$$
the solution of our inequality is:
$$x \leq 1$$
$$\operatorname{asin}{\left(x \right)} \leq \frac{\pi}{2}$$
To solve this inequality, we must first solve the corresponding equation:
$$\operatorname{asin}{\left(x \right)} = \frac{\pi}{2}$$
Solve:
$$x_{1} = 1$$
$$x_{1} = 1$$
This roots
$$x_{1} = 1$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} \leq x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + 1$$
=
$$\frac{9}{10}$$
substitute to the expression
$$\operatorname{asin}{\left(x \right)} \leq \frac{\pi}{2}$$
$$\operatorname{asin}{\left(\frac{9}{10} \right)} \leq \frac{\pi}{2}$$
pi
asin(9/10) <= --
2 the solution of our inequality is:
$$x \leq 1$$
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x1
Solving inequality on a graph