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How to use it?
- Inequation:
- sqrt(-x^2+6x-5)>-2x+8
- x^log625(2+x)>=log5(x^2+4x+4)
- sin(x/6)>sqrt(3)/2
- log(4)(x+30/2)-2>log(4)(x2-3)
- Graphing y =:
- sqrt(-x^2+6x-5)
-
-2x+8
- Canonical form:
- -2x+8
- Integral of d{x}:
-
-2x+8
-
Identical expressions
- sqrt(-x^ two +6x- five)>-2x+ eight
- square root of ( minus x squared plus 6x minus 5) greater than minus 2x plus 8
- square root of ( minus x to the power of two plus 6x minus five) greater than minus 2x plus eight
- √(-x^2+6x-5)>-2x+8
- sqrt(-x2+6x-5)>-2x+8
- sqrt-x2+6x-5>-2x+8
- sqrt(-x²+6x-5)>-2x+8
- sqrt(-x to the power of 2+6x-5)>-2x+8
- sqrt-x^2+6x-5>-2x+8
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Similar expressions
- sqrt(-x^2+6x-5)>+2x+8
- (x^2-4)*(-x^2-2*x+8)<0
- 9^(x-1)>9^((-2)*x)+8
- sqrt(x^2+6x-5)>-2x+8
- sqrt(-x^2-6x-5)>-2x+8
- 4^x-2^x+8⩽257
- sqrt(-x^2+6x-5)>-2x-8
- sqrt(-x^2+6x+5)>-2x+8
- -2(x+8)>=-4x+10
sqrt(-x^2+6x-5)>-2x+8 inequation
The solution
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________________ / 2 \/ - x + 6*x - 5 > -2*x + 8
$$\sqrt{\left(- x^{2} + 6 x\right) - 5} > 8 - 2 x$$
sqrt(-x^2 + 6*x - 5) > 8 - 2*x
Solving inequality on a graph