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sqrt(5^x-625)+log^2x+x<=6 inequation

A inequation with variable

The solution

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  /  x             2            
\/  5  - 625  + log (x) + x <= 6
$$x + \left(\sqrt{5^{x} - 625} + \log{\left(x \right)}^{2}\right) \leq 6$$
x + sqrt(5^x - 625) + log(x)^2 <= 6
Solving inequality on a graph