Given the inequality: sin(7x)>2(−1)3 To solve this inequality, we must first solve the corresponding equation: sin(7x)=2(−1)3 Solve: Given the equation sin(7x)=2(−1)3 - this is the simplest trigonometric equation This equation is transformed to 7x=2πn+asin(−23) 7x=2πn−asin(−23)+π Or 7x=2πn−3π 7x=2πn+34π , where n - is a integer Divide both parts of the equation by 7 x1=72πn−21π x2=72πn+214π x1=72πn−21π x2=72πn+214π This roots x1=72πn−21π x2=72πn+214π is the points with change the sign of the inequality expression. First define with the sign to the leftmost point: x0<x1 For example, let's take the point x0=x1−101 = (72πn−21π)−101 = 72πn−21π−101 substitute to the expression sin(7x)>2(−1)3 sin(7⋅(72πn−21π−101))>2(−1)3