Given the inequality:
$$- x + \left(\frac{1}{16}\right)^{9} < \frac{1}{3}$$
To solve this inequality, we must first solve the corresponding equation:
$$- x + \left(\frac{1}{16}\right)^{9} = \frac{1}{3}$$
Solve:
Given the linear equation:
1/16^9-x = 1/3
Move free summands (without x)
from left part to right part, we given:
$$- x = \frac{68719476733}{206158430208}$$
Divide both parts of the equation by -1
x = 68719476733/206158430208 / (-1)
$$x_{1} = - \frac{68719476733}{206158430208}$$
$$x_{1} = - \frac{68719476733}{206158430208}$$
This roots
$$x_{1} = - \frac{68719476733}{206158430208}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{68719476733}{206158430208} + - \frac{1}{10}$$
=
$$- \frac{446676598769}{1030792151040}$$
substitute to the expression
$$- x + \left(\frac{1}{16}\right)^{9} < \frac{1}{3}$$
$$\left(\frac{1}{16}\right)^{9} - - \frac{446676598769}{1030792151040} < \frac{1}{3}$$
13
-- < 1/3
30
but
13
-- > 1/3
30
Then
$$x < - \frac{68719476733}{206158430208}$$
no execute
the solution of our inequality is:
$$x > - \frac{68719476733}{206158430208}$$
_____
/
-------ο-------
x1