3 |x - 2| > - x
|x - 2| > 3/x
Or(And(-oo < x, x < 0), And(3 < x, x < oo))
((-oo < x)∧(x < 0))∨((3 < x)∧(x < oo))
(-oo, 0) U (3, oo)
x in Union(Interval.open(-oo, 0), Interval.open(3, oo))