Mister Exam

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How to use it?
Inequation:
x-5/(2x-1)^2>0
sgrt(2*x+3)<x
5^(x^2+x)>-1
tan(3*x+pi/6)<0
Identical expressions
(-x- one + three)/ two <= two *x+ seven *x- seven / six - two / three
( minus x minus 1 plus 3) divide by 2 less than or equal to 2 multiply by x plus 7 multiply by x minus 7 divide by 6 minus 2 divide by 3
( minus x minus one plus three) divide by two less than or equal to two multiply by x plus seven multiply by x minus seven divide by six minus two divide by three
(-x-1+3)/2<=2x+7x-7/6-2/3
-x-1+3/2<=2x+7x-7/6-2/3
(-x-1+3) divide by 2<=2*x+7*x-7 divide by 6-2 divide by 3
Similar expressions
(-x-1+3)/2<=2*x+7*x-7/6+2/3
(-x-1+3)/2<=2*x-7*x-7/6-2/3
(-x-1+3)/2<=2*x+7*x+7/6-2/3
(-x+1+3)/2<=2*x+7*x-7/6-2/3
(-x-1-3)/2<=2*x+7*x-7/6-2/3
(x-1+3)/2<=2*x+7*x-7/6-2/3

(-x-1+3)/2<=2x+7x-7/6-2/3 inequation

You have entered [src]

-x - 1 + 3                         
---------- <= 2*x + 7*x - 7/6 - 2/3
    2

$$\frac{\left(- x - 1\right) + 3}{2} \leq \left(\left(2 x + 7 x\right) - \frac{7}{6}\right) - \frac{2}{3}$$

(-x - 1 + 3)/2 <= 2*x + 7*x - 7/6 - 2/3

Solving inequality on a graph

Rapid solution [src]

   /17             \
And|-- <= x, x < oo|
   \57             /

$$\frac{17}{57} \leq x \wedge x < \infty$$

(17/57 <= x)∧(x < oo)

Rapid solution 2 [src]

 17     
[--, oo)
 57

$$x\ in\ \left[\frac{17}{57}, \infty\right)$$

x in Interval(17/57, oo)

(-x-1+3)/2<=2*x+7*x-7/6-2/3 inequation