Given the inequality:
−2cos(3x)>1To solve this inequality, we must first solve the corresponding equation:
−2cos(3x)=1Solve:
Given the equation
−2cos(3x)=1- this is the simplest trigonometric equation
Divide both parts of the equation by -2
The equation is transformed to
cos(3x)=−21This equation is transformed to
3x=πn+acos(−21)3x=πn−π+acos(−21)Or
3x=πn+32π3x=πn−3π, where n - is a integer
Divide both parts of the equation by
31x1=3πn+2πx2=3πn−πx1=3πn+2πx2=3πn−πThis roots
x1=3πn+2πx2=3πn−πis the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
x0<x1For example, let's take the point
x0=x1−101=
(3πn+2π)+−101=
3πn−101+2πsubstitute to the expression
−2cos(3x)>1−2cos(33πn−101+2π)>1 / 1 pi \
2*sin|- -- + -- + pi*n| > 1
\ 30 6 /
Then
x<3πn+2πno execute
one of the solutions of our inequality is:
x>3πn+2π∧x<3πn−π _____
/ \
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x1 x2