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-
How to use it?
- Inequation:
- (x+10)*1/2>x-2
- (1/2)^(2x+1)<4
- -6×>12
- (x^2+1)/(x^2-1)<=o
- Integral of d{x}:
-
12
- Canonical form:
- 12
- Derivative of:
- 12
-
Identical expressions
- - six ×> twelve
- minus 6× greater than 12
- minus six × greater than twelve
-
Similar expressions
- 6×>12
- (x-6)×(3x+1)÷((x+2)(2x-5))<0
- logx^2,(x+1)^2<=1
- (2x^2+5x-3)×(x-3)<=(x^2-x-6)×(x+3)
-6×>12 inequation
The solution
Detail solution
Given the inequality:
$$- 6 x > 12$$
To solve this inequality, we must first solve the corresponding equation:
$$- 6 x = 12$$
Solve:
Given the linear equation:
Divide both parts of the equation by -6
$$x_{1} = -2$$
$$x_{1} = -2$$
This roots
$$x_{1} = -2$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-2 + - \frac{1}{10}$$
=
$$- \frac{21}{10}$$
substitute to the expression
$$- 6 x > 12$$
$$- \frac{\left(-21\right) 6}{10} > 12$$
the solution of our inequality is:
$$x < -2$$
$$- 6 x > 12$$
To solve this inequality, we must first solve the corresponding equation:
$$- 6 x = 12$$
Solve:
Given the linear equation:
-6*x = 12
Divide both parts of the equation by -6
x = 12 / (-6)
$$x_{1} = -2$$
$$x_{1} = -2$$
This roots
$$x_{1} = -2$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$-2 + - \frac{1}{10}$$
=
$$- \frac{21}{10}$$
substitute to the expression
$$- 6 x > 12$$
$$- \frac{\left(-21\right) 6}{10} > 12$$
63/5 > 12
the solution of our inequality is:
$$x < -2$$
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Solving inequality on a graph