Mister Exam
Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
- Logarithmic inequality online
-
How to use it?
- Inequation:
- xy>-4
- (log(x^2+9)/log(3))*log((4/5))*(3*x)/(x+2)-log((4/5))*(6-x)<=0
- (2^2-x)>2c-3
- 1-x>3-2*x
- Sum of series:
-
-8
- Limit of the function:
- -8
- Integral of d{x}:
-
-8
-
Identical expressions
- - four *x+ three >- eight
- minus 4 multiply by x plus 3 greater than minus 8
- minus four multiply by x plus three greater than minus eight
- -4x+3>-8
-
Similar expressions
- 4*x+3>-8
- 2x-3/4>x+1/6-4x+3/3
- -4*x+3>+8
- sqrt(3+x)>sqrt(x^2-4x+3)
- |x*x-4x+3|+2<2*|x-1|+|x-3|
- -4*x-3>-8
-4*x+3>-8 inequation
The solution
Detail solution
Given the inequality:
$$3 - 4 x > -8$$
To solve this inequality, we must first solve the corresponding equation:
$$3 - 4 x = -8$$
Solve:
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = -11$$
Divide both parts of the equation by -4
$$x_{1} = \frac{11}{4}$$
$$x_{1} = \frac{11}{4}$$
This roots
$$x_{1} = \frac{11}{4}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + \frac{11}{4}$$
=
$$\frac{53}{20}$$
substitute to the expression
$$3 - 4 x > -8$$
$$3 - \frac{4 \cdot 53}{20} > -8$$
the solution of our inequality is:
$$x < \frac{11}{4}$$
$$3 - 4 x > -8$$
To solve this inequality, we must first solve the corresponding equation:
$$3 - 4 x = -8$$
Solve:
Given the linear equation:
-4*x+3 = -8
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = -11$$
Divide both parts of the equation by -4
x = -11 / (-4)
$$x_{1} = \frac{11}{4}$$
$$x_{1} = \frac{11}{4}$$
This roots
$$x_{1} = \frac{11}{4}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + \frac{11}{4}$$
=
$$\frac{53}{20}$$
substitute to the expression
$$3 - 4 x > -8$$
$$3 - \frac{4 \cdot 53}{20} > -8$$
-38/5 > -8
the solution of our inequality is:
$$x < \frac{11}{4}$$
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Solving inequality on a graph
Rapid solution 2
[src]
(-oo, 11/4)
$$x\ in\ \left(-\infty, \frac{11}{4}\right)$$
x in Interval.open(-oo, 11/4)
Rapid solution
[src]
And(-oo < x, x < 11/4)
$$-\infty < x \wedge x < \frac{11}{4}$$
(-oo < x)∧(x < 11/4)