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log(x+6)-ln(x)>1/3 inequation

A inequation with variable

The solution

You have entered [src]
log(x + 6) - log(x) > 1/3
$$- \log{\left(x \right)} + \log{\left(x + 6 \right)} > \frac{1}{3}$$
-log(x) + log(x + 6) > 1/3
Solving inequality on a graph
Rapid solution [src]
   /               6    \
And|0 < x, x < ---------|
   |                 1/3|
   \           -1 + e   /
$$0 < x \wedge x < \frac{6}{-1 + e^{\frac{1}{3}}}$$
(0 < x)∧(x < 6/(-1 + exp(1/3)))
Rapid solution 2 [src]
      -6     
(0, --------)
         1/3 
    1 - e    
$$x\ in\ \left(0, - \frac{6}{1 - e^{\frac{1}{3}}}\right)$$
x in Interval.open(0, -6/(1 - exp(1/3)))