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Inequation
:
3^(x^2-5x+6)<27
((2x+3)^2(x-3)^4)/((1-x)(x+5)^3)<=0
5/(cosx+1)<11-2cosx
(2*3^(2x+1)-7*6^(x)+2*4^(x))/(3*9^(x)-3^(x)*2^(x+1))>=1
Integral of d{x}
:
log(x+1)
2*x/(x+2)
Derivative of
:
log(x+1)
2*x/(x+2)
Identical expressions
log(x+ one)> two *x/(x+ two)
logarithm of (x plus 1) greater than 2 multiply by x divide by (x plus 2)
logarithm of (x plus one) greater than two multiply by x divide by (x plus two)
log(x+1)>2x/(x+2)
logx+1>2x/x+2
log(x+1)>2*x divide by (x+2)
Similar expressions
(1-2*x)/(x+2)<=-2
(3-2*x)/(x+2)>0
log2(x-1)-log2(x+1)+logx+1/x-1(2)>0
(3-2*x)/(x+2)<=0
10/(4-2x)/(x+2)<=0
log^2(((7-x)/(x+1))^2)/log(x+8)<=1-log((x+1)/(x-7))/log(x+8)
logx+1(2)-1/logx(x+1)>=0
(log(x)+1)/x+2/(x^(1/2))+2/(9*x^(9/2))<=10^(-8)
log(x+1)>2*x/(x-2)
log(x-1)>2*x/(x+2)
Solving inequalities
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log(x+1)>2*x/(x+2)
log(x+1)>2*x/(x+2) inequation
+ inequation
Solve the inequality!
A inequation with variable
The solution
You have entered
[src]
2*x log(x + 1) > ----- x + 2
$$\log{\left(x + 1 \right)} > \frac{2 x}{x + 2}$$
log(x + 1) > (2*x)/(x + 2)
Solving inequality on a graph