Mister Exam
log1/2(2x+1)>+2 inequation
The solution
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[src]
log(1) ------*(2*x + 1) > 2 2
$$\frac{\log{\left(1 \right)}}{2} \left(2 x + 1\right) > 2$$
(log(1)/2)*(2*x + 1) > 2
Detail solution
Given the inequality:
$$\frac{\log{\left(1 \right)}}{2} \left(2 x + 1\right) > 2$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\log{\left(1 \right)}}{2} \left(2 x + 1\right) = 2$$
Solve:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
$$\frac{\log{\left(1 \right)}}{2} \left(0 \cdot 2 + 1\right) > 2$$
so the inequality has no solutions
$$\frac{\log{\left(1 \right)}}{2} \left(2 x + 1\right) > 2$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\log{\left(1 \right)}}{2} \left(2 x + 1\right) = 2$$
Solve:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$\frac{\log{\left(1 \right)}}{2} \left(0 \cdot 2 + 1\right) > 2$$
0 > 2
so the inequality has no solutions
Rapid solution
This inequality has no solutions