Mister Exam
Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
- Logarithmic inequality online
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How to use it?
- Inequation:
- (x+1)*log((2),(12))+log((2),(3^x-(1/12)))<=(2x-1)
- ((a+2)*x^2)-2ax+a-2<0
- log(3-2x)<2log5-1
- -x^2-10*x-24<=0
- Sum of series:
-
-2
- Integral of d{x}:
-
-2
- Derivative of:
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-2
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Identical expressions
- log one / two (two x+1)>-2
- logarithm of 1 divide by 2(2x plus 1) greater than minus 2
- logarithm of one divide by two (two x plus 1) greater than minus 2
- log1/22x+1>-2
- log1 divide by 2(2x+1)>-2
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Similar expressions
- log1/2(2x+1)>+2
- log1/2(2x-1)>-2
- log1/2(2*x+1)>=-3
log1/2(2x+1)>-2 inequation
The solution
You have entered
[src]
log(1)*(2*x + 1)
---------------- > -2
2
$$\frac{\left(2 x + 1\right) \log{\left(1 \right)}}{2} > -2$$
log(1)*(2*x + 1)/2 > -2
Detail solution
Given the inequality:
$$\frac{\left(2 x + 1\right) \log{\left(1 \right)}}{2} > -2$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\left(2 x + 1\right) \log{\left(1 \right)}}{2} = -2$$
Solve:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
$$\frac{\left(2 \cdot 0 + 1\right) \log{\left(1 \right)}}{2} > -2$$
so the inequality is always executed
$$\frac{\left(2 x + 1\right) \log{\left(1 \right)}}{2} > -2$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\left(2 x + 1\right) \log{\left(1 \right)}}{2} = -2$$
Solve:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$\frac{\left(2 \cdot 0 + 1\right) \log{\left(1 \right)}}{2} > -2$$
0 > -2
so the inequality is always executed