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Inequation
:
12*log(2*u)-20>=log(2)/((2*u))
log(5*x^2+3)/log(x^2-6*x+10)^2<=log(4*x^2+7*x+3)/log(x^2-6*x+10)
(x+19,2)/(x-5)<0
(x-2)(x+5)^2/-x-2>0
Identical expressions
log5(one +x)>log5(-x)
logarithm of 5(1 plus x) greater than logarithm of 5( minus x)
logarithm of 5(one plus x) greater than logarithm of 5( minus x)
log51+x>log5-x
Similar expressions
log5(1+x)>log5(x)
2*(x+3)^(1/7)>log(5-x)^7+1
log5(1-x)>log5(-x)
2log(5-x)>0
log((3-x)*(x^2+2))>=log(x^2-7x+12)+log(5-x)
log((5-x)^2)/log(sqrt(2))>=x^2*log((x+5)^2)/log2+x*log(5-x)/log(1/sqrt(2))
Solving inequalities
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log5(1+x)>log5(-x)
log5(1+x)>log5(-x) inequation
+ inequation
Solve the inequality!
A inequation with variable
The solution
You have entered
[src]
log(1 + x) log(-x) ---------- > ------- log(5) log(5)
$$\frac{\log{\left(x + 1 \right)}}{\log{\left(5 \right)}} > \frac{\log{\left(- x \right)}}{\log{\left(5 \right)}}$$
log(x + 1)/log(5) > log(-x)/log(5)
Solving inequality on a graph