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Inequation
:
log3(8−6x)<log32x
2sin^2x-4sinx*cosx+9cos^2x>o
9c^2+d^2+4-3cd-6c-2d
log_(x-2)(24-6x)<log_(x-2)(2x-3)
Identical expressions
log3(eight −6x)<log32x
logarithm of 3(8−6x) less than logarithm of 32x
logarithm of 3(eight −6x) less than logarithm of 32x
log38−6x<log32x
Similar expressions
log3(2x+1)<log3(5)
log16(x^2-6x+9)>=(1/5)*x^2*log32(x-3)
log(32*x)-1/(log(x))^2-log(x^5)>=-1
log(3)*(x+2)+log(3)*x<log(3)*(2x+1)
Solving inequalities
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log3(8−6x)
log3(8−6x)
+ inequation
Solve the inequality!
A inequation with variable
The solution
You have entered
[src]
log(8 - 6*x) ------------ < log(32*x) log(3)
$$\frac{\log{\left(8 - 6 x \right)}}{\log{\left(3 \right)}} < \log{\left(32 x \right)}$$
log(8 - 6*x)/log(3) < log(32*x)
Solving inequality on a graph