Mister Exam
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How to use it?
- Inequation:
- 9log7(x^2+x-2)<=10+log7((x-1)9/(x+2))
- log3(8−6x)<log32x
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sinx>=0.5
- 9c^2+d^2+4-3cd-6c-2d
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Identical expressions
- log3(eight −6x)<log32x
- logarithm of 3(8−6x) less than logarithm of 32x
- logarithm of 3(eight −6x) less than logarithm of 32x
- log38−6x<log32x
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Similar expressions
- log(32*x)-1/(log(x))^2-log(x^5)>=-1
- log16(x^2-6x+9)>=(1/5)*x^2*log32(x-3)
- log3(2x+1)<log3(5)
- log(3)*(2*x+1)+log(3)*(1/32(x^2)+1)>=log(3)*(1/(16x)+1)
log3(8−6x)
The solution
You have entered
[src]
log(8 - 6*x)
------------ < log(32*x)
log(3)
$$\frac{\log{\left(8 - 6 x \right)}}{\log{\left(3 \right)}} < \log{\left(32 x \right)}$$
log(8 - 6*x)/log(3) < log(32*x)
Solving inequality on a graph
The solution
You have entered
[src]
log(8 - 6*x) ------------ < log(32*x) log(3)
$$\frac{\log{\left(8 - 6 x \right)}}{\log{\left(3 \right)}} < \log{\left(32 x \right)}$$
log(8 - 6*x)/log(3) < log(32*x)
Solving inequality on a graph