ln(4x-5)≥ln(3x-6) inequation

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log(4*x - 5) >= log(3*x - 6)

$$\log{\left(4 x - 5 \right)} \geq \log{\left(3 x - 6 \right)}$$

log(4*x - 5) >= log(3*x - 6)

Solving inequality on a graph

Rapid solution [src]

And(2 < x, x < oo)

$$2 < x \wedge x < \infty$$

(2 < x)∧(x < oo)

Rapid solution 2 [src]

(2, oo)

$$x\ in\ \left(2, \infty\right)$$

x in Interval.open(2, oo)