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lg(2x-3)≥lg(3x-5) inequation

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log(2*x - 3) >= log(3*x - 5)

$$\log{\left(2 x - 3 \right)} \geq \log{\left(3 x - 5 \right)}$$

log(2*x - 3) >= log(3*x - 5)

Solving inequality on a graph

Rapid solution 2 [src]

(5/3, 2]

$$x\ in\ \left(\frac{5}{3}, 2\right]$$

x in Interval.Lopen(5/3, 2)

Rapid solution [src]

And(x <= 2, 5/3 < x)

$$x \leq 2 \wedge \frac{5}{3} < x$$

(x <= 2)∧(5/3 < x)