lg2x>lg(x+1) inequation

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log(2*x) > log(x + 1)

$$\log{\left(2 x \right)} > \log{\left(x + 1 \right)}$$

log(2*x) > log(x + 1)

Solving inequality on a graph

Rapid solution 2 [src]

(1, oo)

$$x\ in\ \left(1, \infty\right)$$

x in Interval.open(1, oo)

Rapid solution [src]

And(1 < x, x < oo)

$$1 < x \wedge x < \infty$$

(1 < x)∧(x < oo)