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Inequation:
7*x^2-5*x-2>0
(3^x)*(9^x+2)>=81
(3x^2-12)/(2x+4)>=0
log(x/(x+3))(6,7)>0
Identical expressions
eleven - four *t< one - six *t
11 minus 4 multiply by t less than 1 minus 6 multiply by t
eleven minus four multiply by t less than one minus six multiply by t
11-4t<1-6t
Similar expressions
11-4t>4-6t
11+4*t<1-6*t
11-4*t<1+6*t

Solving inequalities/ 11-4*t<1-6*t

11-4t<1-6t inequation

The solution

You have entered [src]

11 - 4*t < 1 - 6*t

$$11 - 4 t < 1 - 6 t$$

11 - 4*t < 1 - 6*t

Rapid solution 2 [src]

(-oo, -5)

$$x\ in\ \left(-\infty, -5\right)$$

x in Interval.open(-oo, -5)

Rapid solution [src]

And(-oo < t, t < -5)

$$-\infty < t \wedge t < -5$$

(-oo < t)∧(t < -5)