Mister Exam
Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
- Logarithmic inequality online
-
How to use it?
- Inequation:
- 2sqrt(x)<7-|x-10|
- (3-x)²>=6(1-b)
- x^2-2*x-2*1/x^2-2*x+7*x-19*1/x-3-8*x+1*1/x<=0
- (x^2+x+1)^((x-10)/(x-3))<=(x^2+x+1)^3
- Derivative of:
-
9x
-
-2
- Integral of d{x}:
-
9x
-
-2
- Canonical form:
- 9x
- Sum of series:
-
-2
-
Identical expressions
- 9x<- two
- 9x less than minus 2
- 9x less than minus two
-
Similar expressions
- 9x<+2
- (3^x)*(9^x+2)>=81
- (x^2-19*x+84)/(2*(x-5))>0
- 27^x+1/3-10*9^x+10*3^x-5<0
9x<-2 inequation
The solution
Detail solution
Given the inequality:
$$9 x < -2$$
To solve this inequality, we must first solve the corresponding equation:
$$9 x = -2$$
Solve:
Given the linear equation:
Divide both parts of the equation by 9
$$x_{1} = - \frac{2}{9}$$
$$x_{1} = - \frac{2}{9}$$
This roots
$$x_{1} = - \frac{2}{9}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{2}{9} + - \frac{1}{10}$$
=
$$- \frac{29}{90}$$
substitute to the expression
$$9 x < -2$$
$$\frac{\left(-29\right) 9}{90} < -2$$
the solution of our inequality is:
$$x < - \frac{2}{9}$$
$$9 x < -2$$
To solve this inequality, we must first solve the corresponding equation:
$$9 x = -2$$
Solve:
Given the linear equation:
9*x = -2
Divide both parts of the equation by 9
x = -2 / (9)
$$x_{1} = - \frac{2}{9}$$
$$x_{1} = - \frac{2}{9}$$
This roots
$$x_{1} = - \frac{2}{9}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{2}{9} + - \frac{1}{10}$$
=
$$- \frac{29}{90}$$
substitute to the expression
$$9 x < -2$$
$$\frac{\left(-29\right) 9}{90} < -2$$
-29 ---- < -2 10
the solution of our inequality is:
$$x < - \frac{2}{9}$$
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Solving inequality on a graph
Rapid solution
[src]
And(-oo < x, x < -2/9)
$$-\infty < x \wedge x < - \frac{2}{9}$$
(-oo < x)∧(x < -2/9)
Rapid solution 2
[src]
(-oo, -2/9)
$$x\ in\ \left(-\infty, - \frac{2}{9}\right)$$
x in Interval.open(-oo, -2/9)