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cot(x+pi/6)>=sqrt(3)/3 inequation

A inequation with variable

The solution

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   /    pi\    \/ 3 
cot|x + --| >= -----
   \    6 /      3  
$$\cot{\left(x + \frac{\pi}{6} \right)} \geq \frac{\sqrt{3}}{3}$$
cot(x + pi/6) >= sqrt(3)/3
Detail solution
Given the inequality:
$$\cot{\left(x + \frac{\pi}{6} \right)} \geq \frac{\sqrt{3}}{3}$$
To solve this inequality, we must first solve the corresponding equation:
$$\cot{\left(x + \frac{\pi}{6} \right)} = \frac{\sqrt{3}}{3}$$
Solve:
$$x_{1} = \frac{\pi}{6}$$
$$x_{1} = \frac{\pi}{6}$$
This roots
$$x_{1} = \frac{\pi}{6}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} \leq x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{1}{10} + \frac{\pi}{6}$$
=
$$- \frac{1}{10} + \frac{\pi}{6}$$
substitute to the expression
$$\cot{\left(x + \frac{\pi}{6} \right)} \geq \frac{\sqrt{3}}{3}$$
$$\cot{\left(\left(- \frac{1}{10} + \frac{\pi}{6}\right) + \frac{\pi}{6} \right)} \geq \frac{\sqrt{3}}{3}$$
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   /1    pi\    \/ 3 
tan|-- + --| >= -----
   \10   6 /      3  
                

the solution of our inequality is:
$$x \leq \frac{\pi}{6}$$
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       x1
Rapid solution 2 [src]
    pi     5*pi     
[0, --] U (----, pi]
    6       6       
$$x\ in\ \left[0, \frac{\pi}{6}\right] \cup \left(\frac{5 \pi}{6}, \pi\right]$$
x in Union(Interval(0, pi/6), Interval.Lopen(5*pi/6, pi))
Rapid solution [src]
  /   /             pi\     /         5*pi    \\
Or|And|0 <= x, x <= --|, And|x <= pi, ---- < x||
  \   \             6 /     \          6      //
$$\left(0 \leq x \wedge x \leq \frac{\pi}{6}\right) \vee \left(x \leq \pi \wedge \frac{5 \pi}{6} < x\right)$$
((0 <= x)∧(x <= pi/6))∨((x <= pi)∧(5*pi/6 < x))