Mister Exam
Other calculators
- Square Inequality Step-by-Step
- Inequality with the module Step by Step
- Logarithmic inequality online
-
How to use it?
- Inequation:
- (x+5)*(x+8)<=0
-
cos(x/5)>(-sqrt(2)/2)
- 1-2*sin(4*x)<cos(4*x)^2
- tan(x+pi/6)>1/(sqrt(3))
- Limit of the function:
-
sqrt(3)/3
-
Identical expressions
- cot((pi/ four)- two *x)>sqrt(three)/ three
- cotangent of (( Pi divide by 4) minus 2 multiply by x) greater than square root of (3) divide by 3
- cotangent of (( Pi divide by four) minus two multiply by x) greater than square root of (three) divide by three
- cot((pi/4)-2*x)>√(3)/3
- cot((pi/4)-2x)>sqrt(3)/3
- cotpi/4-2x>sqrt3/3
- cot((pi divide by 4)-2*x)>sqrt(3) divide by 3
-
Similar expressions
- ctg4x<=sqrt3/3
- cot((pi/4)+2*x)>sqrt(3)/3
- cot(x-2*pi/3)>=(-sqrt(3))/3
cot((pi/4)-2*x)>sqrt(3)/3 inequation
The solution
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[src]
___ /pi \ \/ 3 cot|-- - 2*x| > ----- \4 / 3
$$\cot{\left(- 2 x + \frac{\pi}{4} \right)} > \frac{\sqrt{3}}{3}$$
cot(-2*x + pi/4) > sqrt(3)/3
Detail solution
Given the inequality:
$$\cot{\left(- 2 x + \frac{\pi}{4} \right)} > \frac{\sqrt{3}}{3}$$
To solve this inequality, we must first solve the corresponding equation:
$$\cot{\left(- 2 x + \frac{\pi}{4} \right)} = \frac{\sqrt{3}}{3}$$
Solve:
$$x_{1} = - \frac{\pi}{24}$$
$$x_{1} = - \frac{\pi}{24}$$
This roots
$$x_{1} = - \frac{\pi}{24}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{\pi}{24} - \frac{1}{10}$$
=
$$- \frac{\pi}{24} - \frac{1}{10}$$
substitute to the expression
$$\cot{\left(- 2 x + \frac{\pi}{4} \right)} > \frac{\sqrt{3}}{3}$$
$$\cot{\left(- 2 \left(- \frac{\pi}{24} - \frac{1}{10}\right) + \frac{\pi}{4} \right)} > \frac{\sqrt{3}}{3}$$
Then
$$x < - \frac{\pi}{24}$$
no execute
the solution of our inequality is:
$$x > - \frac{\pi}{24}$$
$$\cot{\left(- 2 x + \frac{\pi}{4} \right)} > \frac{\sqrt{3}}{3}$$
To solve this inequality, we must first solve the corresponding equation:
$$\cot{\left(- 2 x + \frac{\pi}{4} \right)} = \frac{\sqrt{3}}{3}$$
Solve:
$$x_{1} = - \frac{\pi}{24}$$
$$x_{1} = - \frac{\pi}{24}$$
This roots
$$x_{1} = - \frac{\pi}{24}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{\pi}{24} - \frac{1}{10}$$
=
$$- \frac{\pi}{24} - \frac{1}{10}$$
substitute to the expression
$$\cot{\left(- 2 x + \frac{\pi}{4} \right)} > \frac{\sqrt{3}}{3}$$
$$\cot{\left(- 2 \left(- \frac{\pi}{24} - \frac{1}{10}\right) + \frac{\pi}{4} \right)} > \frac{\sqrt{3}}{3}$$
___
/1 pi\ \/ 3
cot|- + --| > -----
\5 3 / 3
Then
$$x < - \frac{\pi}{24}$$
no execute
the solution of our inequality is:
$$x > - \frac{\pi}{24}$$
_____
/
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x1