1-2*sin(4*x)<cos(4*x)^2 inequation

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How to use it?
Inequation:
(x+5)*(x+8)<=0
cos(x/5)>(-sqrt(2)/2)
1-2*sin(4*x)<cos(4*x)^2
tan(x+pi/6)>1/(sqrt(3))
Identical expressions
one - two *sin(four *x)<cos(four *x)^ two
1 minus 2 multiply by sinus of (4 multiply by x) less than co sinus of e of (4 multiply by x) squared
one minus two multiply by sinus of (four multiply by x) less than co sinus of e of (four multiply by x) to the power of two
1-2*sin(4*x)<cos(4*x)2
1-2*sin4*x<cos4*x2
1-2*sin(4*x)<cos(4*x)²
1-2*sin(4*x)<cos(4*x) to the power of 2
1-2sin(4x)<cos(4x)^2
1-2sin(4x)<cos(4x)2
1-2sin4x<cos4x2
1-2sin4x<cos4x^2
Similar expressions
1-2sin4x<sqrt(cos)(4x)
1+2*sin(4*x)<cos(4*x)^2
1-2sin4x<cos^2(4x)

                    2     
1 - 2*sin(4*x) < cos (4*x)

$$1 - 2 \sin{\left(4 x \right)} < \cos^{2}{\left(4 x \right)}$$

1 - 2*sin(4*x) < cos(4*x)^2

Solving inequality on a graph

Rapid solution [src]

   /           pi\
And|0 < x, x < --|
   \           4 /

$$0 < x \wedge x < \frac{\pi}{4}$$

(0 < x)∧(x < pi/4)

Rapid solution 2 [src]

    pi 
(0, --)
    4

$$x\ in\ \left(0, \frac{\pi}{4}\right)$$

x in Interval.open(0, pi/4)