Given the inequality:
$$\left(9 x^{2} + 8 x\right) - 16 < 0$$
To solve this inequality, we must first solve the corresponding equation:
$$\left(9 x^{2} + 8 x\right) - 16 = 0$$
Solve:
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 9$$
$$b = 8$$
$$c = -16$$
, then
D = b^2 - 4 * a * c =
(8)^2 - 4 * (9) * (-16) = 640
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = - \frac{4}{9} + \frac{4 \sqrt{10}}{9}$$
$$x_{2} = - \frac{4 \sqrt{10}}{9} - \frac{4}{9}$$
$$x_{1} = - \frac{4}{9} + \frac{4 \sqrt{10}}{9}$$
$$x_{2} = - \frac{4 \sqrt{10}}{9} - \frac{4}{9}$$
$$x_{1} = - \frac{4}{9} + \frac{4 \sqrt{10}}{9}$$
$$x_{2} = - \frac{4 \sqrt{10}}{9} - \frac{4}{9}$$
This roots
$$x_{2} = - \frac{4 \sqrt{10}}{9} - \frac{4}{9}$$
$$x_{1} = - \frac{4}{9} + \frac{4 \sqrt{10}}{9}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} < x_{2}$$
For example, let's take the point
$$x_{0} = x_{2} - \frac{1}{10}$$
=
$$\left(- \frac{4 \sqrt{10}}{9} - \frac{4}{9}\right) + - \frac{1}{10}$$
=
$$- \frac{4 \sqrt{10}}{9} - \frac{49}{90}$$
substitute to the expression
$$\left(9 x^{2} + 8 x\right) - 16 < 0$$
$$-16 + \left(8 \left(- \frac{4 \sqrt{10}}{9} - \frac{49}{90}\right) + 9 \left(- \frac{4 \sqrt{10}}{9} - \frac{49}{90}\right)^{2}\right) < 0$$
2
/ ____\ ____
916 | 49 4*\/ 10 | 32*\/ 10 < 0
- --- + 9*|- -- - --------| - ---------
45 \ 90 9 / 9 but
2
/ ____\ ____
916 | 49 4*\/ 10 | 32*\/ 10 > 0
- --- + 9*|- -- - --------| - ---------
45 \ 90 9 / 9 Then
$$x < - \frac{4 \sqrt{10}}{9} - \frac{4}{9}$$
no execute
one of the solutions of our inequality is:
$$x > - \frac{4 \sqrt{10}}{9} - \frac{4}{9} \wedge x < - \frac{4}{9} + \frac{4 \sqrt{10}}{9}$$
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/ \
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x2 x1