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  • Graphing y =:
  • (x+5)^2(x-1)+7
  • x-3/4-x
  • x^3+3*x^2-9*x
  • x^3-16x
  • Derivative of:
  • (x^2-1)/((2*x)) (x^2-1)/((2*x))
  • Identical expressions

  • (x^ two - one)/((two *x))
  • (x squared minus 1) divide by ((2 multiply by x))
  • (x to the power of two minus one) divide by ((two multiply by x))
  • (x2-1)/((2*x))
  • x2-1/2*x
  • (x²-1)/((2*x))
  • (x to the power of 2-1)/((2*x))
  • (x^2-1)/((2x))
  • (x2-1)/((2x))
  • x2-1/2x
  • x^2-1/2x
  • (x^2-1) divide by ((2*x))
  • Similar expressions

  • (x^2+1)/((2*x))

Graphing y = (x^2-1)/((2*x))

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
        2    
       x  - 1
f(x) = ------
        2*x  
$$f{\left(x \right)} = \frac{x^{2} - 1}{2 x}$$
f = (x^2 - 1)/((2*x))
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 0$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{x^{2} - 1}{2 x} = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = -1$$
$$x_{2} = 1$$
Numerical solution
$$x_{1} = 1$$
$$x_{2} = -1$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to (x^2 - 1)/((2*x)).
$$\frac{-1 + 0^{2}}{0 \cdot 2}$$
The result:
$$f{\left(0 \right)} = \tilde{\infty}$$
sof doesn't intersect Y
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$2 \frac{1}{2 x} x - \frac{x^{2} - 1}{2 x^{2}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{-1 + \frac{x^{2} - 1}{x^{2}}}{x} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = 0$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{x^{2} - 1}{2 x}\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{x^{2} - 1}{2 x}\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of (x^2 - 1)/((2*x)), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\frac{1}{2 x} \left(x^{2} - 1\right)}{x}\right) = \frac{1}{2}$$
Let's take the limit
so,
inclined asymptote equation on the left:
$$y = \frac{x}{2}$$
$$\lim_{x \to \infty}\left(\frac{\frac{1}{2 x} \left(x^{2} - 1\right)}{x}\right) = \frac{1}{2}$$
Let's take the limit
so,
inclined asymptote equation on the right:
$$y = \frac{x}{2}$$
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{x^{2} - 1}{2 x} = - \frac{x^{2} - 1}{2 x}$$
- No
$$\frac{x^{2} - 1}{2 x} = \frac{x^{2} - 1}{2 x}$$
- No
so, the function
not is
neither even, nor odd