Mister Exam

Other calculators

Plotting a function graph/ (x^2-4x+3)/(x-2)

Graphing y = (x^2-4x+3)/(x-2)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src] 
        2          
       x  - 4*x + 3
f(x) = ------------
          x - 2
f(x)=(x2−4x)+3x−2f{\left(x \right)} = \frac{\left(x^{2} - 4 x\right) + 3}{x - 2} 
f = (x^2 - 4*x + 3)/(x - 2)
The graph of the function
02468-8-6-4-2-1010-5050
The domain of the function
The points at which the function is not precisely defined:
x1=2x_{1} = 2
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
(x2−4x)+3x−2=0\frac{\left(x^{2} - 4 x\right) + 3}{x - 2} = 0
Solve this equation
The points of intersection with the axis X:

Analytical solution
x1=1x_{1} = 1
x2=3x_{2} = 3
Numerical solution
x1=1x_{1} = 1
x2=3x_{2} = 3
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to (x^2 - 4*x + 3)/(x - 2).
(02−0)+3−2\frac{\left(0^{2} - 0\right) + 3}{-2}
The result:
f(0)=−32f{\left(0 \right)} = - \frac{3}{2}
The point:
(0, -3/2)
Extrema of the function
In order to find the extrema, we need to solve the equation
ddxf(x)=0\frac{d}{d x} f{\left(x \right)} = 0
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
ddxf(x)=\frac{d}{d x} f{\left(x \right)} =
the first derivative
2x−4x−2−(x2−4x)+3(x−2)2=0\frac{2 x - 4}{x - 2} - \frac{\left(x^{2} - 4 x\right) + 3}{\left(x - 2\right)^{2}} = 0
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
d2dx2f(x)=0\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
d2dx2f(x)=\frac{d^{2}}{d x^{2}} f{\left(x \right)} =
the second derivative
2(−1+x2−4x+3(x−2)2)x−2=0\frac{2 \left(-1 + \frac{x^{2} - 4 x + 3}{\left(x - 2\right)^{2}}\right)}{x - 2} = 0
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
x1=2x_{1} = 2
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
lim⁡x→−∞((x2−4x)+3x−2)=−∞\lim_{x \to -\infty}\left(\frac{\left(x^{2} - 4 x\right) + 3}{x - 2}\right) = -\infty
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
lim⁡x→∞((x2−4x)+3x−2)=∞\lim_{x \to \infty}\left(\frac{\left(x^{2} - 4 x\right) + 3}{x - 2}\right) = \infty
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of (x^2 - 4*x + 3)/(x - 2), divided by x at x->+oo and x ->-oo
lim⁡x→−∞((x2−4x)+3x(x−2))=1\lim_{x \to -\infty}\left(\frac{\left(x^{2} - 4 x\right) + 3}{x \left(x - 2\right)}\right) = 1
Let's take the limit
so,
inclined asymptote equation on the left:
y=xy = x
lim⁡x→∞((x2−4x)+3x(x−2))=1\lim_{x \to \infty}\left(\frac{\left(x^{2} - 4 x\right) + 3}{x \left(x - 2\right)}\right) = 1
Let's take the limit
so,
inclined asymptote equation on the right:
y=xy = x
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
(x2−4x)+3x−2=x2+4x+3−x−2\frac{\left(x^{2} - 4 x\right) + 3}{x - 2} = \frac{x^{2} + 4 x + 3}{- x - 2}
- No
(x2−4x)+3x−2=−x2+4x+3−x−2\frac{\left(x^{2} - 4 x\right) + 3}{x - 2} = - \frac{x^{2} + 4 x + 3}{- x - 2}
- No
so, the function
not is
neither even, nor odd
    © Mister Exam – Calculator