Mister Exam
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-
How to use it?
- Graphing y =:
- x^2-4x+3
-
x^2-4x
- x^2+4
- 3x+2
-
Identical expressions
- x^ three -3x^ two +9x
- x cubed minus 3x squared plus 9x
- x to the power of three minus 3x to the power of two plus 9x
- x3-3x2+9x
- x³-3x²+9x
- x to the power of 3-3x to the power of 2+9x
-
Similar expressions
- x^3+3x^2+9x
- x^3-3x^2-9x
Graphing y = x^3-3x^2+9x
The solution
You have entered
[src]
3 2 f(x) = x - 3*x + 9*x
$$f{\left(x \right)} = 9 x + \left(x^{3} - 3 x^{2}\right)$$
f = 9*x + x^3 - 3*x^2
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$9 x + \left(x^{3} - 3 x^{2}\right) = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
so we need to solve the equation:
$$9 x + \left(x^{3} - 3 x^{2}\right) = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$3 x^{2} - 6 x + 9 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$3 x^{2} - 6 x + 9 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$6 \left(x - 1\right) = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 1$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left[1, \infty\right)$$
Convex at the intervals
$$\left(-\infty, 1\right]$$
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$6 \left(x - 1\right) = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 1$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left[1, \infty\right)$$
Convex at the intervals
$$\left(-\infty, 1\right]$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(9 x + \left(x^{3} - 3 x^{2}\right)\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(9 x + \left(x^{3} - 3 x^{2}\right)\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
$$\lim_{x \to -\infty}\left(9 x + \left(x^{3} - 3 x^{2}\right)\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(9 x + \left(x^{3} - 3 x^{2}\right)\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of x^3 - 3*x^2 + 9*x, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{9 x + \left(x^{3} - 3 x^{2}\right)}{x}\right) = \infty$$
Let's take the limit
so,
inclined asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{9 x + \left(x^{3} - 3 x^{2}\right)}{x}\right) = \infty$$
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
$$\lim_{x \to -\infty}\left(\frac{9 x + \left(x^{3} - 3 x^{2}\right)}{x}\right) = \infty$$
Let's take the limit
so,
inclined asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{9 x + \left(x^{3} - 3 x^{2}\right)}{x}\right) = \infty$$
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$9 x + \left(x^{3} - 3 x^{2}\right) = - x^{3} - 3 x^{2} - 9 x$$
- No
$$9 x + \left(x^{3} - 3 x^{2}\right) = x^{3} + 3 x^{2} + 9 x$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$9 x + \left(x^{3} - 3 x^{2}\right) = - x^{3} - 3 x^{2} - 9 x$$
- No
$$9 x + \left(x^{3} - 3 x^{2}\right) = x^{3} + 3 x^{2} + 9 x$$
- No
so, the function
not is
neither even, nor odd