Mister Exam
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-
How to use it?
- Graphing y =:
- x^3-12x+24
- -x^2+5*x+4
- x^2+4x+2
- (x^2-4x+1)/(x-4)
- Integral of d{x}:
-
(x+4)/(x+1)
- Derivative of:
-
(x+4)/(x+1)
-
Identical expressions
- (x+ four)/(x+ one)
- (x plus 4) divide by (x plus 1)
- (x plus four) divide by (x plus one)
- x+4/x+1
- (x+4) divide by (x+1)
-
Similar expressions
- (x+4)/(x-1)
- x^3*(3x+4)/(x+1)^3
- x+4/(x+1)
- y=x+4/x+14
- (x^2-5x+4)/(x+1)
- x^3(3*x+4)/(x+1)^3
- (x-4)/(x+1)
Graphing y = (x+4)/(x+1)
The solution
You have entered
[src]
x + 4
f(x) = -----
x + 1
$$f{\left(x \right)} = \frac{x + 4}{x + 1}$$
f = (x + 4)/(x + 1)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = -1$$
$$x_{1} = -1$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{x + 4}{x + 1} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = -4$$
Numerical solution
$$x_{1} = -4$$
so we need to solve the equation:
$$\frac{x + 4}{x + 1} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = -4$$
Numerical solution
$$x_{1} = -4$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{1}{x + 1} - \frac{x + 4}{\left(x + 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{1}{x + 1} - \frac{x + 4}{\left(x + 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(-1 + \frac{x + 4}{x + 1}\right)}{\left(x + 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(-1 + \frac{x + 4}{x + 1}\right)}{\left(x + 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = -1$$
$$x_{1} = -1$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{x + 4}{x + 1}\right) = 1$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 1$$
$$\lim_{x \to \infty}\left(\frac{x + 4}{x + 1}\right) = 1$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 1$$
$$\lim_{x \to -\infty}\left(\frac{x + 4}{x + 1}\right) = 1$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 1$$
$$\lim_{x \to \infty}\left(\frac{x + 4}{x + 1}\right) = 1$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 1$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of (x + 4)/(x + 1), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{x + 4}{x \left(x + 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{x + 4}{x \left(x + 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{x + 4}{x \left(x + 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{x + 4}{x \left(x + 1\right)}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{x + 4}{x + 1} = \frac{4 - x}{1 - x}$$
- No
$$\frac{x + 4}{x + 1} = - \frac{4 - x}{1 - x}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\frac{x + 4}{x + 1} = \frac{4 - x}{1 - x}$$
- No
$$\frac{x + 4}{x + 1} = - \frac{4 - x}{1 - x}$$
- No
so, the function
not is
neither even, nor odd