Mister Exam

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  • How to use it?

  • Graphing y =:
  • x^-6
  • x^3-3x-20
  • -x^3-2
  • x^2+9x+14
  • Identical expressions

  • x- three (sqrtx^ two)
  • x minus 3( square root of x squared )
  • x minus three ( square root of x to the power of two)
  • x-3(√x^2)
  • x-3(sqrtx2)
  • x-3sqrtx2
  • x-3(sqrtx²)
  • x-3(sqrtx to the power of 2)
  • x-3sqrtx^2
  • Similar expressions

  • x+3(sqrtx^2)

Graphing y = x-3(sqrtx^2)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(x) = x - 3*\/ x  
$$f{\left(x \right)} = - 3 \left(\sqrt{x}\right)^{2} + x$$
f = -3*x + x
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$- 3 \left(\sqrt{x}\right)^{2} + x = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to x - 3*x.
$$- 3 \left(\sqrt{0}\right)^{2}$$
The result:
$$f{\left(0 \right)} = 0$$
The point:
(0, 0)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$-2 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(- 3 \left(\sqrt{x}\right)^{2} + x\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(- 3 \left(\sqrt{x}\right)^{2} + x\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of x - 3*x, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{- 3 \left(\sqrt{x}\right)^{2} + x}{x}\right) = -2$$
Let's take the limit
so,
inclined asymptote equation on the left:
$$y = - 2 x$$
$$\lim_{x \to \infty}\left(\frac{- 3 \left(\sqrt{x}\right)^{2} + x}{x}\right) = -2$$
Let's take the limit
so,
inclined asymptote equation on the right:
$$y = - 2 x$$
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$- 3 \left(\sqrt{x}\right)^{2} + x = 2 x$$
- No
$$- 3 \left(\sqrt{x}\right)^{2} + x = - 2 x$$
- No
so, the function
not is
neither even, nor odd