Mister Exam
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-
How to use it?
- Graphing y =:
- x^4/(1+x)^3
- (x^3-3x^2+4)
- (x^3)-3x+2
- x*е^x
- Integral of d{x}:
-
x/(x^3-x)
- Limit of the function:
-
x/(x^3-x)
-
Identical expressions
- x/(x^ three -x)
- x divide by (x cubed minus x)
- x divide by (x to the power of three minus x)
- x/(x3-x)
- x/x3-x
- x/(x³-x)
- x/(x to the power of 3-x)
- x/x^3-x
- x divide by (x^3-x)
-
Similar expressions
- x/(x^3+x)
Graphing y = x/(x^3-x)
The solution
You have entered
[src]
x
f(x) = ------
3
x - x
$$f{\left(x \right)} = \frac{x}{x^{3} - x}$$
f = x/(x^3 - x)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = -1$$
$$x_{2} = 0$$
$$x_{3} = 1$$
$$x_{1} = -1$$
$$x_{2} = 0$$
$$x_{3} = 1$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{x}{x^{3} - x} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
so we need to solve the equation:
$$\frac{x}{x^{3} - x} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{x \left(1 - 3 x^{2}\right)}{\left(x^{3} - x\right)^{2}} + \frac{1}{x^{3} - x} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{x \left(1 - 3 x^{2}\right)}{\left(x^{3} - x\right)^{2}} + \frac{1}{x^{3} - x} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- \frac{2 \left(3 + \frac{3 x^{2} - 1}{x^{2}} - \frac{\left(3 x^{2} - 1\right)^{2}}{x^{2} \left(x^{2} - 1\right)}\right)}{\left(x^{2} - 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- \frac{2 \left(3 + \frac{3 x^{2} - 1}{x^{2}} - \frac{\left(3 x^{2} - 1\right)^{2}}{x^{2} \left(x^{2} - 1\right)}\right)}{\left(x^{2} - 1\right)^{2}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = -1$$
$$x_{2} = 0$$
$$x_{3} = 1$$
$$x_{1} = -1$$
$$x_{2} = 0$$
$$x_{3} = 1$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{x}{x^{3} - x}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(\frac{x}{x^{3} - x}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
$$\lim_{x \to -\infty}\left(\frac{x}{x^{3} - x}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(\frac{x}{x^{3} - x}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of x/(x^3 - x), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty} \frac{1}{x^{3} - x} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty} \frac{1}{x^{3} - x} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty} \frac{1}{x^{3} - x} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty} \frac{1}{x^{3} - x} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{x}{x^{3} - x} = - \frac{x}{- x^{3} + x}$$
- No
$$\frac{x}{x^{3} - x} = \frac{x}{- x^{3} + x}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\frac{x}{x^{3} - x} = - \frac{x}{- x^{3} + x}$$
- No
$$\frac{x}{x^{3} - x} = \frac{x}{- x^{3} + x}$$
- No
so, the function
not is
neither even, nor odd