Graphing y = 3(x+3)

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f(x) = 3*(x + 3)

f{\left(x \right)} = 3 \left(x + 3\right)

f = 3*(x + 3)

The graph of the function

The points of intersection with the X-axis coordinate

Graph of the function intersects the axis X at f = 0
so we need to solve the equation:

3 \left(x + 3\right) = 0

Solve this equation
The points of intersection with the axis X:

Analytical solution

x_{1} = -3

Numerical solution

x_{1} = -3

The points of intersection with the Y axis coordinate

The graph crosses Y axis when x equals 0:
substitute x = 0 to 3*(x + 3).

3 \cdot 3

The result:

f{\left(0 \right)} = 9

The point:

(0, 9)

Extrema of the function

In order to find the extrema, we need to solve the equation

\frac{d}{d x} f{\left(x \right)} = 0

(the derivative equals zero),
and the roots of this equation are the extrema of this function:

\frac{d}{d x} f{\left(x \right)} =

3 = 0

Solve this equation
Solutions are not found,
function may have no extrema

Inflection points

Let's find the inflection points, we'll need to solve the equation for this

\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0

(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:

\frac{d^{2}}{d x^{2}} f{\left(x \right)} =

0 = 0

Solve this equation
Solutions are not found,
maybe, the function has no inflections

Horizontal asymptotes

Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo

\lim_{x \to -\infty}\left(3 \left(x + 3\right)\right) = -\infty

Let's take the limit
so,
horizontal asymptote on the left doesn’t exist

\lim_{x \to \infty}\left(3 \left(x + 3\right)\right) = \infty

Let's take the limit
so,
horizontal asymptote on the right doesn’t exist

Inclined asymptotes

Inclined asymptote can be found by calculating the limit of 3*(x + 3), divided by x at x->+oo and x ->-oo

\lim_{x \to -\infty}\left(\frac{3 \left(x + 3\right)}{x}\right) = 3

Let's take the limit
so,
inclined asymptote equation on the left:

y = 3 x

\lim_{x \to \infty}\left(\frac{3 \left(x + 3\right)}{x}\right) = 3

Let's take the limit
so,
inclined asymptote equation on the right:

y = 3 x

Even and odd functions

Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:

3 \left(x + 3\right) = 9 - 3 x

- No

3 \left(x + 3\right) = 3 x - 9

- No
so, the function
not is
neither even, nor odd