Mister Exam

Graphing y = sqrt(y)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
         ___
f(y) = \/ y 
$$f{\left(y \right)} = \sqrt{y}$$
f = sqrt(y)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis Y at f = 0
so we need to solve the equation:
$$\sqrt{y} = 0$$
Solve this equation
The points of intersection with the axis Y:

Analytical solution
$$y_{1} = 0$$
Numerical solution
$$y_{1} = 0$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when y equals 0:
substitute y = 0 to sqrt(y).
$$\sqrt{0}$$
The result:
$$f{\left(0 \right)} = 0$$
The point:
(0, 0)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d y} f{\left(y \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d y} f{\left(y \right)} = $$
the first derivative
$$\frac{1}{2 \sqrt{y}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d y^{2}} f{\left(y \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d y^{2}} f{\left(y \right)} = $$
the second derivative
$$- \frac{1}{4 y^{\frac{3}{2}}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at y->+oo and y->-oo
$$\lim_{y \to -\infty} \sqrt{y} = \infty i$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{y \to \infty} \sqrt{y} = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt(y), divided by y at y->+oo and y ->-oo
$$\lim_{y \to -\infty} \frac{1}{\sqrt{y}} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{y \to \infty} \frac{1}{\sqrt{y}} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-y) и f = -f(-y).
So, check:
$$\sqrt{y} = \sqrt{- y}$$
- No
$$\sqrt{y} = - \sqrt{- y}$$
- No
so, the function
not is
neither even, nor odd