Mister Exam
Graphing y = sqrt(2)-x+sqrt(3)+x
The solution
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___ ___ f(x) = \/ 2 - x + \/ 3 + x
$$f{\left(x \right)} = x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)$$
f = x - x + sqrt(2) + sqrt(3)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right) = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
so we need to solve the equation:
$$x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right) = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)\right) = \sqrt{2} + \sqrt{3}$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = \sqrt{2} + \sqrt{3}$$
$$\lim_{x \to \infty}\left(x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)\right) = \sqrt{2} + \sqrt{3}$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = \sqrt{2} + \sqrt{3}$$
$$\lim_{x \to -\infty}\left(x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)\right) = \sqrt{2} + \sqrt{3}$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = \sqrt{2} + \sqrt{3}$$
$$\lim_{x \to \infty}\left(x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)\right) = \sqrt{2} + \sqrt{3}$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = \sqrt{2} + \sqrt{3}$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt(2) - x + sqrt(3) + x, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right) = \sqrt{2} + \sqrt{3}$$
- No
$$x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right) = - \sqrt{3} - \sqrt{2}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right) = \sqrt{2} + \sqrt{3}$$
- No
$$x + \left(\left(- x + \sqrt{2}\right) + \sqrt{3}\right) = - \sqrt{3} - \sqrt{2}$$
- No
so, the function
not is
neither even, nor odd