Mister Exam

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  • Graphing y =:
  • x^2+3x+3
  • -x^2-2x+1
  • x^2+14x+15
  • x^2-2lnx
  • Identical expressions

  • sqrt(three *x)- eighteen
  • square root of (3 multiply by x) minus 18
  • square root of (three multiply by x) minus eighteen
  • √(3*x)-18
  • sqrt(3x)-18
  • sqrt3x-18
  • Similar expressions

  • sqrt(3*x)+18

Graphing y = sqrt(3*x)-18

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(x) = \/ 3*x  - 18
$$f{\left(x \right)} = \sqrt{3 x} - 18$$
f = sqrt(3*x) - 18
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\sqrt{3 x} - 18 = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = 108$$
Numerical solution
$$x_{1} = 108$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to sqrt(3*x) - 18.
$$-18 + \sqrt{0 \cdot 3}$$
The result:
$$f{\left(0 \right)} = -18$$
The point:
(0, -18)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{\sqrt{3} \sqrt{x}}{2 x} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- \frac{\sqrt{3}}{4 x^{\frac{3}{2}}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\sqrt{3 x} - 18\right) = \infty i$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\sqrt{3 x} - 18\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt(3*x) - 18, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\sqrt{3 x} - 18}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\sqrt{3 x} - 18}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\sqrt{3 x} - 18 = \sqrt{3} \sqrt{- x} - 18$$
- No
$$\sqrt{3 x} - 18 = - \sqrt{3} \sqrt{- x} + 18$$
- No
so, the function
not is
neither even, nor odd