Mister Exam

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  • How to use it?

  • Graphing y =:
  • x/(3+x^2)
  • x^3-9*x
  • (x-2)(x+4)
  • x^2-5*x
  • Identical expressions

  • sqrt(one -sin^2x/sin^2x)
  • square root of (1 minus sinus of squared x divide by sinus of squared x)
  • square root of (one minus sinus of squared x divide by sinus of squared x)
  • √(1-sin^2x/sin^2x)
  • sqrt(1-sin2x/sin2x)
  • sqrt1-sin2x/sin2x
  • sqrt(1-sin²x/sin²x)
  • sqrt(1-sin to the power of 2x/sin to the power of 2x)
  • sqrt1-sin^2x/sin^2x
  • sqrt(1-sin^2x divide by sin^2x)
  • Similar expressions

  • sqrt(1+sin^2x/sin^2x)

Graphing y = sqrt(1-sin^2x/sin^2x)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
             _____________
            /        2    
           /      sin (x) 
f(x) =    /   1 - ------- 
         /           2    
       \/         sin (x) 
$$f{\left(x \right)} = \sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1}$$
f = sqrt(-sin(x)^2/sin(x)^2 + 1)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 0$$
$$x_{2} = 3.14159265358979$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to sqrt(1 - sin(x)^2/sin(x)^2).
$$\sqrt{- \frac{\sin^{2}{\left(0 \right)}}{\sin^{2}{\left(0 \right)}} + 1}$$
The result:
$$f{\left(0 \right)} = \text{NaN}$$
- the solutions of the equation d'not exist
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{- \frac{\sin{\left(x \right)} \cos{\left(x \right)}}{\sin^{2}{\left(x \right)}} + \frac{\cos{\left(x \right)}}{\sin{\left(x \right)}}}{\sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\text{NaN} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = 0$$
$$x_{2} = 3.14159265358979$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty} \sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt(1 - sin(x)^2/sin(x)^2), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1} = \sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1}$$
- Yes
$$\sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1} = - \sqrt{- \frac{\sin^{2}{\left(x \right)}}{\sin^{2}{\left(x \right)}} + 1}$$
- No
so, the function
is
even