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Graphing y = sqrt((|2x-3|))

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(x) = \/ |2*x - 3| 
f(x)=2x3f{\left(x \right)} = \sqrt{\left|{2 x - 3}\right|}
f = sqrt(|2*x - 3|)
The graph of the function
02468-8-6-4-2-101005
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
2x3=0\sqrt{\left|{2 x - 3}\right|} = 0
Solve this equation
The points of intersection with the axis X:

Analytical solution
x1=32x_{1} = \frac{3}{2}
Numerical solution
x1=1.5x_{1} = 1.5
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to sqrt(|2*x - 3|).
3+02\sqrt{\left|{-3 + 0 \cdot 2}\right|}
The result:
f(0)=3f{\left(0 \right)} = \sqrt{3}
The point:
(0, sqrt(3))
Extrema of the function
In order to find the extrema, we need to solve the equation
ddxf(x)=0\frac{d}{d x} f{\left(x \right)} = 0
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
ddxf(x)=\frac{d}{d x} f{\left(x \right)} =
the first derivative
sign(2x3)2x3=0\frac{\operatorname{sign}{\left(2 x - 3 \right)}}{\sqrt{\left|{2 x - 3}\right|}} = 0
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
d2dx2f(x)=0\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
d2dx2f(x)=\frac{d^{2}}{d x^{2}} f{\left(x \right)} =
the second derivative
4δ(2x3)sign2(2x3)2x32x3=0\frac{4 \delta\left(2 x - 3\right) - \frac{\operatorname{sign}^{2}{\left(2 x - 3 \right)}}{\left|{2 x - 3}\right|}}{\sqrt{\left|{2 x - 3}\right|}} = 0
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
limx2x3=\lim_{x \to -\infty} \sqrt{\left|{2 x - 3}\right|} = \infty
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
limx2x3=\lim_{x \to \infty} \sqrt{\left|{2 x - 3}\right|} = \infty
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt(|2*x - 3|), divided by x at x->+oo and x ->-oo
limx(2x3x)=0\lim_{x \to -\infty}\left(\frac{\sqrt{\left|{2 x - 3}\right|}}{x}\right) = 0
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
limx(2x3x)=0\lim_{x \to \infty}\left(\frac{\sqrt{\left|{2 x - 3}\right|}}{x}\right) = 0
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
2x3=2x+3\sqrt{\left|{2 x - 3}\right|} = \sqrt{\left|{2 x + 3}\right|}
- No
2x3=2x+3\sqrt{\left|{2 x - 3}\right|} = - \sqrt{\left|{2 x + 3}\right|}
- No
so, the function
not is
neither even, nor odd