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Graphing y = sqrt(3x-5)+sqrt(3x+11)

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The graph:

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Intersection points:

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Piecewise:

The solution

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         _________     __________
f(x) = \/ 3*x - 5  + \/ 3*x + 11 
$$f{\left(x \right)} = \sqrt{3 x - 5} + \sqrt{3 x + 11}$$
f = sqrt(3*x - 5) + sqrt(3*x + 11)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\sqrt{3 x - 5} + \sqrt{3 x + 11} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to sqrt(3*x - 5) + sqrt(3*x + 11).
$$\sqrt{0 \cdot 3 + 11} + \sqrt{-5 + 0 \cdot 3}$$
The result:
$$f{\left(0 \right)} = \sqrt{11} + \sqrt{5} i$$
The point:
(0, sqrt(11) + i*sqrt(5))
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{3}{2 \sqrt{3 x + 11}} + \frac{3}{2 \sqrt{3 x - 5}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- \frac{9 \left(\frac{1}{\left(3 x + 11\right)^{\frac{3}{2}}} + \frac{1}{\left(3 x - 5\right)^{\frac{3}{2}}}\right)}{4} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\sqrt{3 x - 5} + \sqrt{3 x + 11}\right) = \infty i$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\sqrt{3 x - 5} + \sqrt{3 x + 11}\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt(3*x - 5) + sqrt(3*x + 11), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\sqrt{3 x - 5} + \sqrt{3 x + 11}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\sqrt{3 x - 5} + \sqrt{3 x + 11}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\sqrt{3 x - 5} + \sqrt{3 x + 11} = \sqrt{11 - 3 x} + \sqrt{- 3 x - 5}$$
- No
$$\sqrt{3 x - 5} + \sqrt{3 x + 11} = - \sqrt{11 - 3 x} - \sqrt{- 3 x - 5}$$
- No
so, the function
not is
neither even, nor odd