The points at which the function is not precisely defined: x1=0 x2=6.28318530717959
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0 so we need to solve the equation: −cos(x)+1sin(x)=0 Solve this equation The points of intersection with the axis X:
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0: substitute x = 0 to sin(x)/(sqrt(1 - cos(x))). −cos(0)+1sin(0) The result: f(0)=NaN - the solutions of the equation d'not exist
Extrema of the function
In order to find the extrema, we need to solve the equation dxdf(x)=0 (the derivative equals zero), and the roots of this equation are the extrema of this function: dxdf(x)= the first derivative −cos(x)+1cos(x)−2(−cos(x)+1)23sin2(x)=0 Solve this equation Solutions are not found, function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this dx2d2f(x)=0 (the second derivative equals zero), the roots of this equation will be the inflection points for the specified function graph: dx2d2f(x)= the second derivative −−cos(x)+1(1+4⋅(−cos(x)+1)2cos(x)+cos(x)−13sin2(x)+−cos(x)+1cos(x))sin(x)=0 Solve this equation The roots of this equation x1=π You also need to calculate the limits of y '' for arguments seeking to indeterminate points of a function: Points where there is an indetermination: x1=0 x2=6.28318530717959
x→0−lim−−cos(x)+1(1+4⋅(−cos(x)+1)2cos(x)+cos(x)−13sin2(x)+−cos(x)+1cos(x))sin(x)=42 Let's take the limit x→0+lim−−cos(x)+1(1+4⋅(−cos(x)+1)2cos(x)+cos(x)−13sin2(x)+−cos(x)+1cos(x))sin(x)=−42 Let's take the limit - the limits are not equal, so x1=0 - is an inflection point x→6.28318530717959−lim−−cos(x)+1(1+4⋅(−cos(x)+1)2cos(x)+cos(x)−13sin2(x)+−cos(x)+1cos(x))sin(x)=−∞ Let's take the limit x→6.28318530717959+lim−−cos(x)+1(1+4⋅(−cos(x)+1)2cos(x)+cos(x)−13sin2(x)+−cos(x)+1cos(x))sin(x)=∞i Let's take the limit - the limits are not equal, so x2=6.28318530717959 - is an inflection point
Сonvexity and concavity intervals: Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points: Concave at the intervals [π,∞) Convex at the intervals (−∞,π]
Vertical asymptotes
Have: x1=0 x2=6.28318530717959
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo x→−∞lim(−cos(x)+1sin(x))=⟨−∞,∞⟩ Let's take the limit so, equation of the horizontal asymptote on the left: y=⟨−∞,∞⟩ x→∞lim(−cos(x)+1sin(x))=⟨−∞,∞⟩ Let's take the limit so, equation of the horizontal asymptote on the right: y=⟨−∞,∞⟩
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sin(x)/(sqrt(1 - cos(x))), divided by x at x->+oo and x ->-oo x→−∞lim(x−cos(x)+1sin(x))=x→−∞lim(x−cos(x)+1sin(x)) Let's take the limit so, inclined asymptote equation on the left: y=xx→−∞lim(x−cos(x)+1sin(x)) x→∞lim(x−cos(x)+1sin(x))=x→∞lim(x−cos(x)+1sin(x)) Let's take the limit so, inclined asymptote equation on the right: y=xx→∞lim(x−cos(x)+1sin(x))
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x). So, check: −cos(x)+1sin(x)=−−cos(x)+1sin(x) - No −cos(x)+1sin(x)=−cos(x)+1sin(x) - No so, the function not is neither even, nor odd