Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative$$- \frac{\sin{\left(\frac{x}{\pi} \right)}}{\pi^{2}} = 0$$
Solve this equationThe roots of this equation
$$x_{1} = 0$$
$$x_{2} = \pi^{2}$$
Сonvexity and concavity intervals:Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, 0\right] \cup \left[\pi^{2}, \infty\right)$$
Convex at the intervals
$$\left[0, \pi^{2}\right]$$