Mister Exam

Other calculators

  • How to use it?

  • Graphing y =:
  • 2x^4+8/3x^3
  • 2x^2-5x
  • 2x^2+6x
  • 1/3(x^3-14x^2+49x-36)
  • Identical expressions

  • (one - five *x/x+ one)^ four
  • (1 minus 5 multiply by x divide by x plus 1) to the power of 4
  • (one minus five multiply by x divide by x plus one) to the power of four
  • (1-5*x/x+1)4
  • 1-5*x/x+14
  • (1-5*x/x+1)⁴
  • (1-5x/x+1)^4
  • (1-5x/x+1)4
  • 1-5x/x+14
  • 1-5x/x+1^4
  • (1-5*x divide by x+1)^4
  • Similar expressions

  • (1+5*x/x+1)^4
  • (1-5*x/x-1)^4

Graphing y = (1-5*x/x+1)^4

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
                    4
       /    5*x    \ 
f(x) = |1 - --- + 1| 
       \     x     / 
$$f{\left(x \right)} = \left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4}$$
f = (1 - 5*x/x + 1)^4
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 0$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to (1 - 5*x/x + 1)^4.
$$\left(\left(- \frac{0 \cdot 5}{0} + 1\right) + 1\right)^{4}$$
The result:
$$f{\left(0 \right)} = \text{NaN}$$
- the solutions of the equation d'not exist
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = 0$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4} = 81$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 81$$
$$\lim_{x \to \infty} \left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4} = 81$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 81$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of (1 - 5*x/x + 1)^4, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4} = 81$$
- No
$$\left(\left(1 - \frac{5 x}{x}\right) + 1\right)^{4} = -81$$
- No
so, the function
not is
neither even, nor odd